2x^2-50x-1875=0

Solution for 2x^2-50x-1875=0 equation:

2x^2-50x-1875=0

a = 2; b = -50; c = -1875;
Δ = b2-4ac
Δ = -502-4·2·(-1875)
Δ = 17500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17500}=\sqrt{2500*7}=\sqrt{2500}*\sqrt{7}=50\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-50\sqrt{7}}{2*2}=\frac{50-50\sqrt{7}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+50\sqrt{7}}{2*2}=\frac{50+50\sqrt{7}}{4}
$